3y/4-3=y2+3

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Solution for 3y/4-3=y2+3 equation: 


y in (-oo:+oo)

(3*y)/4-3 = y^2+3 // - y^2+3

(3*y)/4-y^2-3-3 = 0

3/4*y-y^2-6 = 0

DELTA = (3/4)^2-(-6*(-1)*4)

DELTA = -375/16

DELTA < 0

y belongs to the empty set

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