3y/4-y/2-2/y=5

Solution for 3y/4-y/2-2/y=5 equation:

D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(3*y)/4-(y/2)-(2/y) = 5 // - 5

(3*y)/4-(y/2)-(2/y)-5 = 0

(3*y)/4-(y/2)-2*y^-1-5 = 0

1/4*y^1-2*y^-1-5*y^0 = 0

(1/4*y^2-5*y^1-2*y^0)/(y^1) = 0 // * y^2

y^1*(1/4*y^2-5*y^1-2*y^0) = 0

y^1

(1/4)*y^2-5*y-2 = 0

(1/4)*y^2-5*y-2 = 0

DELTA = (-5)^2-(-2*4*(1/4))

DELTA = 27

DELTA > 0

y = (27^(1/2)+5)/(2*(1/4)) or y = (5-27^(1/2))/(2*(1/4))

y = 2*(3*3^(1/2)+5) or y = 2*(5-3*3^(1/2))

y in { 2*(5-3*3^(1/2)), 2*(3*3^(1/2)+5)} 

y in { 2*(5-3*3^(1/2)), 2*(3*3^(1/2)+5) }