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3y/5y=-6y
We move all terms to the left:
3y/5y-(-6y)=0
Domain of the equation: 5y!=0We get rid of parentheses
y!=0/5
y!=0
y∈R
3y/5y+6y=0
We multiply all the terms by the denominator
3y+6y*5y=0
Wy multiply elements
30y^2+3y=0
a = 30; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·30·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*30}=\frac{-6}{60} =-1/10 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*30}=\frac{0}{60} =0 $
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