3y/7=32

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Solution for 3y/7=32 equation:



3y/7=32
We move all terms to the left:
3y/7-(32)=0
We multiply all the terms by the denominator
3y-32*7=0
We add all the numbers together, and all the variables
3y-224=0
We move all terms containing y to the left, all other terms to the right
3y=224
y=224/3
y=74+2/3

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