3y/y+3=8-9/y+3

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Solution for 3y/y+3=8-9/y+3 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(3*y)/y+3 = 3-(9/y)+8 // - 3-(9/y)+8

9/y+(3*y)/y-8-3+3 = 0

9*y^-1 = 5 // : 9

y^-1 = 5/9

-1 < 0

1/(y^1) = 5/9 // * y^1

1 = 5/9*y^1 // : 5/9

9/5 = y^1

y = 9/5

y = 9/5

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