3y2+10y=17y2

Solution for 3y2+10y=17y2 equation:

3y^2+10y=17y^2

We move all terms to the left:

3y^2+10y-(17y^2)=0

determiningTheFunctionDomain
3y^2-17y^2+10y=0

We add all the numbers together, and all the variables

-14y^2+10y=0

a = -14; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-14)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-14}=\frac{-20}{-28}
=5/7
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-14}=\frac{0}{-28}
=0
$