3y2+10y=17y2

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Solution for 3y2+10y=17y2 equation:



3y^2+10y=17y^2
We move all terms to the left:
3y^2+10y-(17y^2)=0
determiningTheFunctionDomain 3y^2-17y^2+10y=0
We add all the numbers together, and all the variables
-14y^2+10y=0
a = -14; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-14)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-14}=\frac{-20}{-28} =5/7 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-14}=\frac{0}{-28} =0 $

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