3y2+36+108=48

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Solution for 3y2+36+108=48 equation: 



3y^2+36+108=48

We move all terms to the left:

3y^2+36+108-(48)=0

We add all the numbers together, and all the variables

3y^2+96=0

a = 3; b = 0; c = +96;
Δ = b2-4ac
Δ = 02-4·3·96
Δ = -1152
Delta is less than zero, so there is no solution for the equation

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