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3y^2-51y=0
a = 3; b = -51; c = 0;
Δ = b2-4ac
Δ = -512-4·3·0
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-51}{2*3}=\frac{0}{6} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+51}{2*3}=\frac{102}{6} =17 $
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