3y2-8y+5=0

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Solution for 3y2-8y+5=0 equation: 



3y^2-8y+5=0

a = 3; b = -8; c = +5;
Δ = b2-4ac
Δ = -82-4·3·5
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2}{2*3}=\frac{6}{6}
=1
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2}{2*3}=\frac{10}{6}
=1+2/3
$

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