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3y^2=-2y-1
We move all terms to the left:
3y^2-(-2y-1)=0
We get rid of parentheses
3y^2+2y+1=0
a = 3; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·3·1
Δ = -8
Delta is less than zero, so there is no solution for the equation
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