3y2=504

Solution for 3y2=504 equation:

3y^2=504

We move all terms to the left:

3y^2-(504)=0

a = 3; b = 0; c = -504;
Δ = b2-4ac
Δ = 02-4·3·(-504)
Δ = 6048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6048}=\sqrt{144*42}=\sqrt{144}*\sqrt{42}=12\sqrt{42}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{42}}{2*3}=\frac{0-12\sqrt{42}}{6}
=-\frac{12\sqrt{42}}{6}
=-2\sqrt{42}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{42}}{2*3}=\frac{0+12\sqrt{42}}{6}
=\frac{12\sqrt{42}}{6}
=2\sqrt{42}
$