3y=(8-12y)/4

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Solution for 3y=(8-12y)/4 equation: 



3y=(8-12y)/4

We move all terms to the left:

3y-((8-12y)/4)=0

We add all the numbers together, and all the variables

3y-((-12y+8)/4)=0

We multiply all the terms by the denominator


3y*4)-((-12y+8)=0

Wy multiply elements

12y^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{24}=0$

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