3y=(8-12y/4)+12

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Solution for 3y=(8-12y/4)+12 equation: 



3y=(8-12y/4)+12

We move all terms to the left:

3y-((8-12y/4)+12)=0

We add all the numbers together, and all the variables

3y-((-12y/4+8)+12)=0

We multiply all the terms by the denominator


3y*4-12y+8)+12)-((=0

We add all the numbers together, and all the variables

-12y+3y*4=0

Wy multiply elements

-12y+12y=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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