3y=(y+12)

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Solution for 3y=(y+12) equation:



3y=(y+12)
We move all terms to the left:
3y-((y+12))=0
We calculate terms in parentheses: -((y+12)), so:
(y+12)
We get rid of parentheses
y+12
Back to the equation:
-(y+12)
We get rid of parentheses
3y-y-12=0
We add all the numbers together, and all the variables
2y-12=0
We move all terms containing y to the left, all other terms to the right
2y=12
y=12/2
y=6

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