3y=-7+28/5

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Solution for 3y=-7+28/5 equation: 



3y=-7+28/5

We move all terms to the left:

3y-(-7+28/5)=0

We add all the numbers together, and all the variables

3y-(28/5-7)=0

We get rid of parentheses

3y+7-28/5=0

We multiply all the terms by the denominator


3y*5-28+7*5=0

We add all the numbers together, and all the variables

3y*5+7=0

Wy multiply elements

15y+7=0

We move all terms containing y to the left, all other terms to the right

15y=-7

y=-7/15

y=-7/15

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