3y=2(4-2y)+6

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Solution for 3y=2(4-2y)+6 equation: 



3y=2(4-2y)+6

We move all terms to the left:

3y-(2(4-2y)+6)=0

We add all the numbers together, and all the variables

3y-(2(-2y+4)+6)=0



We calculate terms in parentheses: -(2(-2y+4)+6), so:

2(-2y+4)+6

We multiply parentheses

-4y+8+6

We add all the numbers together, and all the variables

-4y+14

Back to the equation:

-(-4y+14)



We get rid of parentheses

3y+4y-14=0

We add all the numbers together, and all the variables

7y-14=0

We move all terms containing y to the left, all other terms to the right

7y=14

y=14/7

y=2

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