3y=2y-(y/2)

Solution for 3y=2y-(y/2) equation:

3y=2y-(y/2)

We move all terms to the left:

3y-(2y-(y/2))=0

We add all the numbers together, and all the variables

3y-(2y-(+y/2))=0

We multiply all the terms by the denominator


3y*2))-(2y-(+y=0

We add all the numbers together, and all the variables

y+3y*2))-(2y-(=0

Wy multiply elements

6y^2+y=0

a = 6; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·6·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*6}=\frac{-2}{12}
=-1/6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*6}=\frac{0}{12}
=0
$