3y=3(1-y)-y=-6=

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Solution for 3y=3(1-y)-y=-6= equation: 



3y=3(1-y)-y=-6=

We move all terms to the left:

3y-(3(1-y)-y)=0

We add all the numbers together, and all the variables

3y-(3(-1y+1)-y)=0



We calculate terms in parentheses: -(3(-1y+1)-y), so:

3(-1y+1)-y

We add all the numbers together, and all the variables

-1y+3(-1y+1)

We multiply parentheses

-1y-3y+3

We add all the numbers together, and all the variables

-4y+3

Back to the equation:

-(-4y+3)



We get rid of parentheses

3y+4y-3=0

We add all the numbers together, and all the variables

7y-3=0

We move all terms containing y to the left, all other terms to the right

7y=3

y=3/7

y=3/7

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