3y=5(y+3)-3

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Solution for 3y=5(y+3)-3 equation: 



3y=5(y+3)-3

We move all terms to the left:

3y-(5(y+3)-3)=0



We calculate terms in parentheses: -(5(y+3)-3), so:

5(y+3)-3

We multiply parentheses

5y+15-3

We add all the numbers together, and all the variables

5y+12

Back to the equation:

-(5y+12)



We get rid of parentheses

3y-5y-12=0

We add all the numbers together, and all the variables

-2y-12=0

We move all terms containing y to the left, all other terms to the right

-2y=12

y=12/-2

y=-6

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