3y=6+(2+y)

Solution for 3y=6+(2+y) equation:

3y=6+(2+y)

We move all terms to the left:

3y-(6+(2+y))=0

We add all the numbers together, and all the variables

3y-(6+(y+2))=0


We calculate terms in parentheses: -(6+(y+2)), so:

6+(y+2)

determiningTheFunctionDomain
(y+2)+6

We get rid of parentheses

y+2+6

We add all the numbers together, and all the variables

y+8

Back to the equation:

-(y+8)


We get rid of parentheses

3y-y-8=0

We add all the numbers together, and all the variables

2y-8=0

We move all terms containing y to the left, all other terms to the right

2y=8

y=8/2

y=4