3y=6-2(y-2)

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Solution for 3y=6-2(y-2) equation: 



3y=6-2(y-2)

We move all terms to the left:

3y-(6-2(y-2))=0



We calculate terms in parentheses: -(6-2(y-2)), so:

6-2(y-2)

determiningTheFunctionDomain
-2(y-2)+6

We multiply parentheses

-2y+4+6

We add all the numbers together, and all the variables

-2y+10

Back to the equation:

-(-2y+10)



We get rid of parentheses

3y+2y-10=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2

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