3z(z+2)=3(z*z)+6z-6

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Solution for 3z(z+2)=3(z*z)+6z-6 equation: 



3z(z+2)=3(z*z)+6z-6

We move all terms to the left:

3z(z+2)-(3(z*z)+6z-6)=0

We add all the numbers together, and all the variables

3z(z+2)-(3(+z*z)+6z-6)=0

We multiply parentheses

3z^2+6z-(3(+z*z)+6z-6)=0



We calculate terms in parentheses: -(3(+z*z)+6z-6), so:

3(+z*z)+6z-6

We add all the numbers together, and all the variables

6z+3(+z*z)-6

We multiply parentheses

3z^2+6z-6

Back to the equation:

-(3z^2+6z-6)



We get rid of parentheses

3z^2-3z^2+6z-6z+6=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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