3z(z=9)

Solution for 3z(z=9) equation:

3z(z=9)

We move all terms to the left:

3z(z-(9))=0

We multiply parentheses

3z^2-27z=0

a = 3; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·3·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*3}=\frac{0}{6}
=0
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*3}=\frac{54}{6}
=9
$