3z+(-2)=28

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Solution for 3z+(-2)=28 equation: 



3z+(-2)=28

We move all terms to the left:

3z+(-2)-(28)=0

determiningTheFunctionDomain
3z-28+(-2)=0

We add all the numbers together, and all the variables

3z-30=0

We move all terms containing z to the left, all other terms to the right

3z=30

z=30/3

z=10

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