3z+(2z-5)=(z-3)+22

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Solution for 3z+(2z-5)=(z-3)+22 equation: 


Simplifying
3z + (2z + -5) = (z + -3) + 22

Reorder the terms:
3z + (-5 + 2z) = (z + -3) + 22

Remove parenthesis around (-5 + 2z)
3z + -5 + 2z = (z + -3) + 22

Reorder the terms:
-5 + 3z + 2z = (z + -3) + 22

Combine like terms: 3z + 2z = 5z
-5 + 5z = (z + -3) + 22

Reorder the terms:
-5 + 5z = (-3 + z) + 22

Remove parenthesis around (-3 + z)
-5 + 5z = -3 + z + 22

Reorder the terms:
-5 + 5z = -3 + 22 + z

Combine like terms: -3 + 22 = 19
-5 + 5z = 19 + z

Solving
-5 + 5z = 19 + z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-5 + 5z + -1z = 19 + z + -1z

Combine like terms: 5z + -1z = 4z
-5 + 4z = 19 + z + -1z

Combine like terms: z + -1z = 0
-5 + 4z = 19 + 0
-5 + 4z = 19

Add '5' to each side of the equation.
-5 + 5 + 4z = 19 + 5

Combine like terms: -5 + 5 = 0
0 + 4z = 19 + 5
4z = 19 + 5

Combine like terms: 19 + 5 = 24
4z = 24

Divide each side by '4'.
z = 6

Simplifying
z = 6

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