3z+(3z+3)=50

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Solution for 3z+(3z+3)=50 equation:



3z+(3z+3)=50
We move all terms to the left:
3z+(3z+3)-(50)=0
We get rid of parentheses
3z+3z+3-50=0
We add all the numbers together, and all the variables
6z-47=0
We move all terms containing z to the left, all other terms to the right
6z=47
z=47/6
z=7+5/6

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