3z+1-z=6+z+2

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Solution for 3z+1-z=6+z+2 equation: 



3z+1-z=6+z+2

We move all terms to the left:

3z+1-z-(6+z+2)=0

We add all the numbers together, and all the variables

3z-z-(z+8)+1=0

We add all the numbers together, and all the variables

2z-(z+8)+1=0

We get rid of parentheses

2z-z-8+1=0

We add all the numbers together, and all the variables

z-7=0

We move all terms containing z to the left, all other terms to the right

z=7

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