3z+1/5+4z-2/10=z+1/2

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Solution for 3z+1/5+4z-2/10=z+1/2 equation: 


z in (-oo:+oo)

3*z+4*z+1/5-(2/10) = z+1/2 // - z+1/2

3*z+4*z-z+1/5-(2/10)-(1/2) = 0

3*z+4*z-z+1/5-1/5-1/2 = 0

6*z-1/2 = 0 // + 1/2

6*z = 1/2 // : 6

z = 1/2/6

z = 1/12

z = 1/12

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