3z+10+z+16=12

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Solution for 3z+10+z+16=12 equation:



3z+10+z+16=12
We move all terms to the left:
3z+10+z+16-(12)=0
We add all the numbers together, and all the variables
4z+14=0
We move all terms containing z to the left, all other terms to the right
4z=-14
z=-14/4
z=-3+1/2

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