3z+10=2(3z-4)

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Solution for 3z+10=2(3z-4) equation: 



3z+10=2(3z-4)

We move all terms to the left:

3z+10-(2(3z-4))=0



We calculate terms in parentheses: -(2(3z-4)), so:

2(3z-4)

We multiply parentheses

6z-8

Back to the equation:

-(6z-8)



We get rid of parentheses

3z-6z+8+10=0

We add all the numbers together, and all the variables

-3z+18=0

We move all terms containing z to the left, all other terms to the right

-3z=-18

z=-18/-3

z=+6

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