3z+12=24+z

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Solution for 3z+12=24+z equation: 



3z+12=24+z

We move all terms to the left:

3z+12-(24+z)=0

We add all the numbers together, and all the variables

3z-(z+24)+12=0

We get rid of parentheses

3z-z-24+12=0

We add all the numbers together, and all the variables

2z-12=0

We move all terms containing z to the left, all other terms to the right

2z=12

z=12/2

z=6

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