3z+12=34

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Solution for 3z+12=34 equation: 



3z+12=34

We move all terms to the left:

3z+12-(34)=0

We add all the numbers together, and all the variables

3z-22=0

We move all terms containing z to the left, all other terms to the right

3z=22

z=22/3

z=7+1/3

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