3z+12=4

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Solution for 3z+12=4 equation: 



3z+12=4

We move all terms to the left:

3z+12-(4)=0

We add all the numbers together, and all the variables

3z+8=0

We move all terms containing z to the left, all other terms to the right

3z=-8

z=-8/3

z=-2+2/3

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