3z+12=7

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Solution for 3z+12=7 equation: 



3z+12=7

We move all terms to the left:

3z+12-(7)=0

We add all the numbers together, and all the variables

3z+5=0

We move all terms containing z to the left, all other terms to the right

3z=-5

z=-5/3

z=-1+2/3

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