3z+12=9z-16

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Solution for 3z+12=9z-16 equation: 



3z+12=9z-16

We move all terms to the left:

3z+12-(9z-16)=0

We get rid of parentheses

3z-9z+16+12=0

We add all the numbers together, and all the variables

-6z+28=0

We move all terms containing z to the left, all other terms to the right

-6z=-28

z=-28/-6

z=4+2/3

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