3z+15=-4z+29

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Solution for 3z+15=-4z+29 equation: 



3z+15=-4z+29

We move all terms to the left:

3z+15-(-4z+29)=0

We get rid of parentheses

3z+4z-29+15=0

We add all the numbers together, and all the variables

7z-14=0

We move all terms containing z to the left, all other terms to the right

7z=14

z=14/7

z=2

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