3z+15=1z-4

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Solution for 3z+15=1z-4 equation: 



3z+15=1z-4

We move all terms to the left:

3z+15-(1z-4)=0

We add all the numbers together, and all the variables

3z-(z-4)+15=0

We get rid of parentheses

3z-z+4+15=0

We add all the numbers together, and all the variables

2z+19=0

We move all terms containing z to the left, all other terms to the right

2z=-19

z=-19/2

z=-9+1/2

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