3z+18(z+1)=60

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Solution for 3z+18(z+1)=60 equation: 



3z+18(z+1)=60

We move all terms to the left:

3z+18(z+1)-(60)=0

We multiply parentheses

3z+18z+18-60=0

We add all the numbers together, and all the variables

21z-42=0

We move all terms containing z to the left, all other terms to the right

21z=42

z=42/21

z=2

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