3z+19-z=1

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Solution for 3z+19-z=1 equation: 



3z+19-z=1

We move all terms to the left:

3z+19-z-(1)=0

We add all the numbers together, and all the variables

2z+18=0

We move all terms containing z to the left, all other terms to the right

2z=-18

z=-18/2

z=-9

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