3z+2(3+Z)=51

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Solution for 3z+2(3+Z)=51 equation: 



3z+2(3+)=51

We move all terms to the left:

3z+2(3+)-(51)=0

determiningTheFunctionDomain
3z-51+2(3+)=0

We add all the numbers together, and all the variables

3z-51+20=0

We add all the numbers together, and all the variables

3z-31=0

We move all terms containing z to the left, all other terms to the right

3z=31

z=31/3

z=10+1/3

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