3z+2(4-2)=-(z-5)+1

Solution for 3z+2(4-2)=-(z-5)+1 equation:

Simplifying
3z + 2(4 + -2) = -1(z + -5) + 1

Combine like terms: 4 + -2 = 2
3z + 2(2) = -1(z + -5) + 1

Multiply 2 * 2
3z + 4 = -1(z + -5) + 1

Reorder the terms:
4 + 3z = -1(z + -5) + 1

Reorder the terms:
4 + 3z = -1(-5 + z) + 1
4 + 3z = (-5 * -1 + z * -1) + 1
4 + 3z = (5 + -1z) + 1

Reorder the terms:
4 + 3z = 5 + 1 + -1z

Combine like terms: 5 + 1 = 6
4 + 3z = 6 + -1z

Solving
4 + 3z = 6 + -1z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add 'z' to each side of the equation.
4 + 3z + z = 6 + -1z + z

Combine like terms: 3z + z = 4z
4 + 4z = 6 + -1z + z

Combine like terms: -1z + z = 0
4 + 4z = 6 + 0
4 + 4z = 6

Add '-4' to each side of the equation.
4 + -4 + 4z = 6 + -4

Combine like terms: 4 + -4 = 0
0 + 4z = 6 + -4
4z = 6 + -4

Combine like terms: 6 + -4 = 2
4z = 2

Divide each side by '4'.
z = 0.5

Simplifying
z = 0.5