3z+2(4-z)=-(z-1)+1

Solution for 3z+2(4-z)=-(z-1)+1 equation:

3z+2(4-z)=-(z-1)+1

We move all terms to the left:

3z+2(4-z)-(-(z-1)+1)=0

We add all the numbers together, and all the variables

3z+2(-1z+4)-(-(z-1)+1)=0

We multiply parentheses

3z-2z-(-(z-1)+1)+8=0


We calculate terms in parentheses: -(-(z-1)+1), so:

-(z-1)+1

We get rid of parentheses

-z+1+1

We add all the numbers together, and all the variables

-1z+2

Back to the equation:

-(-1z+2)


We add all the numbers together, and all the variables

z-(-1z+2)+8=0

We get rid of parentheses

z+1z-2+8=0

We add all the numbers together, and all the variables

2z+6=0

We move all terms containing z to the left, all other terms to the right

2z=-6

z=-6/2

z=-3