3z+2(4-z)=-(z-5)+1

Solution for 3z+2(4-z)=-(z-5)+1 equation:

Simplifying
3z + 2(4 + -1z) = -1(z + -5) + 1
3z + (4 * 2 + -1z * 2) = -1(z + -5) + 1
3z + (8 + -2z) = -1(z + -5) + 1

Reorder the terms:
8 + 3z + -2z = -1(z + -5) + 1

Combine like terms: 3z + -2z = 1z
8 + 1z = -1(z + -5) + 1

Reorder the terms:
8 + 1z = -1(-5 + z) + 1
8 + 1z = (-5 * -1 + z * -1) + 1
8 + 1z = (5 + -1z) + 1

Reorder the terms:
8 + 1z = 5 + 1 + -1z

Combine like terms: 5 + 1 = 6
8 + 1z = 6 + -1z

Solving
8 + 1z = 6 + -1z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add 'z' to each side of the equation.
8 + 1z + z = 6 + -1z + z

Combine like terms: 1z + z = 2z
8 + 2z = 6 + -1z + z

Combine like terms: -1z + z = 0
8 + 2z = 6 + 0
8 + 2z = 6

Add '-8' to each side of the equation.
8 + -8 + 2z = 6 + -8

Combine like terms: 8 + -8 = 0
0 + 2z = 6 + -8
2z = 6 + -8

Combine like terms: 6 + -8 = -2
2z = -2

Divide each side by '2'.
z = -1

Simplifying
z = -1