3z+2(6-z)=-(z-2)+4

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Solution for 3z+2(6-z)=-(z-2)+4 equation:


Simplifying
3z + 2(6 + -1z) = -1(z + -2) + 4
3z + (6 * 2 + -1z * 2) = -1(z + -2) + 4
3z + (12 + -2z) = -1(z + -2) + 4

Reorder the terms:
12 + 3z + -2z = -1(z + -2) + 4

Combine like terms: 3z + -2z = 1z
12 + 1z = -1(z + -2) + 4

Reorder the terms:
12 + 1z = -1(-2 + z) + 4
12 + 1z = (-2 * -1 + z * -1) + 4
12 + 1z = (2 + -1z) + 4

Reorder the terms:
12 + 1z = 2 + 4 + -1z

Combine like terms: 2 + 4 = 6
12 + 1z = 6 + -1z

Solving
12 + 1z = 6 + -1z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add 'z' to each side of the equation.
12 + 1z + z = 6 + -1z + z

Combine like terms: 1z + z = 2z
12 + 2z = 6 + -1z + z

Combine like terms: -1z + z = 0
12 + 2z = 6 + 0
12 + 2z = 6

Add '-12' to each side of the equation.
12 + -12 + 2z = 6 + -12

Combine like terms: 12 + -12 = 0
0 + 2z = 6 + -12
2z = 6 + -12

Combine like terms: 6 + -12 = -6
2z = -6

Divide each side by '2'.
z = -3

Simplifying
z = -3

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