3z+2-z=6+z+6

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Solution for 3z+2-z=6+z+6 equation: 



3z+2-z=6+z+6

We move all terms to the left:

3z+2-z-(6+z+6)=0

We add all the numbers together, and all the variables

3z-z-(z+12)+2=0

We add all the numbers together, and all the variables

2z-(z+12)+2=0

We get rid of parentheses

2z-z-12+2=0

We add all the numbers together, and all the variables

z-10=0

We move all terms containing z to the left, all other terms to the right

z=10

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