3z+20=4z+6

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Solution for 3z+20=4z+6 equation: 



3z+20=4z+6

We move all terms to the left:

3z+20-(4z+6)=0

We get rid of parentheses

3z-4z-6+20=0

We add all the numbers together, and all the variables

-1z+14=0

We move all terms containing z to the left, all other terms to the right

-z=-14

z=-14/-1

z=+14

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