3z+24=6z+12

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Solution for 3z+24=6z+12 equation: 



3z+24=6z+12

We move all terms to the left:

3z+24-(6z+12)=0

We get rid of parentheses

3z-6z-12+24=0

We add all the numbers together, and all the variables

-3z+12=0

We move all terms containing z to the left, all other terms to the right

-3z=-12

z=-12/-3

z=+4

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