3z+26+2z=-6

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Solution for 3z+26+2z=-6 equation: 



3z+26+2z=-6

We move all terms to the left:

3z+26+2z-(-6)=0

We add all the numbers together, and all the variables

5z+32=0

We move all terms containing z to the left, all other terms to the right

5z=-32

z=-32/5

z=-6+2/5

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