3z+3=3(z+4)-9

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Solution for 3z+3=3(z+4)-9 equation:


Simplifying
3z + 3 = 3(z + 4) + -9

Reorder the terms:
3 + 3z = 3(z + 4) + -9

Reorder the terms:
3 + 3z = 3(4 + z) + -9
3 + 3z = (4 * 3 + z * 3) + -9
3 + 3z = (12 + 3z) + -9

Reorder the terms:
3 + 3z = 12 + -9 + 3z

Combine like terms: 12 + -9 = 3
3 + 3z = 3 + 3z

Add '-3' to each side of the equation.
3 + -3 + 3z = 3 + -3 + 3z

Combine like terms: 3 + -3 = 0
0 + 3z = 3 + -3 + 3z
3z = 3 + -3 + 3z

Combine like terms: 3 + -3 = 0
3z = 0 + 3z
3z = 3z

Add '-3z' to each side of the equation.
3z + -3z = 3z + -3z

Combine like terms: 3z + -3z = 0
0 = 3z + -3z

Combine like terms: 3z + -3z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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