3z+4(8z-6)=151

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Solution for 3z+4(8z-6)=151 equation:



3z+4(8z-6)=151
We move all terms to the left:
3z+4(8z-6)-(151)=0
We multiply parentheses
3z+32z-24-151=0
We add all the numbers together, and all the variables
35z-175=0
We move all terms containing z to the left, all other terms to the right
35z=175
z=175/35
z=5

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